shell 获取当前目录名

basename `pwd`

echo ${PWD##*/}

parameter substitution with the ${var##pattern} syntax, which removes from $var the longest part of $Pattern that matches the front end of $var

pwd | rev | awk –F \/ '{print $1}' | rev

The -F option indicates that you should separate by fields, where the field delimiter is /, and that you should print field 1.

pwd | sed 's,^$.*/$\?$[^/]*$,\2,'